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x^2-4x-572=0
a = 1; b = -4; c = -572;
Δ = b2-4ac
Δ = -42-4·1·(-572)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-48}{2*1}=\frac{-44}{2} =-22 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+48}{2*1}=\frac{52}{2} =26 $
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